Odpovědět:
#x = 2 #
Vysvětlení:
Povolání #sqrt 49 + 20 sqrt 6 = 5 + 2 sqrt 6 = beta # my máme
# (5 + 2 sqrt 6) ^ 1+ (5- 2 sqrt 6) ^ 1 = 10 #
pro
#sqrt (asqrt (asqrt (a … oo))) = 1 # a
# x ^ 2 + x-3 - sqrt (xsqrt (xsqrt (x … oo)) = 1 #
a tak
# a = x ^ 2-3 #
ale
#sqrt (asqrt (asqrt (a … oo))) = a ^ (1/2 + 1/4 + 1/8 + cdots + 1/2 ^ k + cdots) = a ^ 1 = 1 #
a pak
# 1 = x ^ 2-3 rArr x = 2 #
pak
# x ^ 2 + x-3 - sqrt (xsqrt (xsqrt (x … oo)) = 1 #
nebo
# 1 + 2- sqrt (2sqrt (2sqrt (2 … oo)) = 1 #
pak #x = 2 #