Odpovědět:
Viz. níže
Vysvětlení:
# 3sec ^ 2thatan ^ 2theta + 1 = sec ^ 6theta-tan ^ 6theta #
Pravá strana# = sec ^ 6theta-tan ^ 6theta #
# = (sec ^ 2theta) ^ 3- (tan ^ 2theta) ^ 3 #-> použijte rozdíl dvou krychlových vzorců
# = (sec ^ 2theta-tan ^ 2theta) (sec ^ 4theta + sec ^ 2thatan ^ 2theta + tan ^ 4theta) #
# = 1 * (sec ^ 4theta + sec ^ 2theta + 2theta + tan ^ 4theta) #
# = sec ^ 4theta + sec ^ 2thatan ^ 2theta + tan ^ 4theta #
# = sec ^ 2theta sec ^ 2 theta + sec ^ 2theta ^ 2theta + tan ^ 2theta tan ^ 2 theta #
# = sec ^ 2theta (tan ^ 2theta + 1) + sec ^ 2theta + 2theta + 2 ^ theta (sec ^ 2theta-1) #
# = sec ^ 2thatan ^ 2theta + sec ^ 2theta + sec ^ 2tetatan ^ 2theta + sec ^ 2tetatan ^ 2theta-tan ^ 2theta # 2
# = sec ^ 2thatan ^ 2theta + sec ^ 2tetatan ^ 2theta + sec ^ 2tetatan ^ 2theta + sec ^ 2theta-tan ^ 2theta # 2
# = 3sec ^ 2thatan ^ 2theta + 1 #
#=# Levá strana