Co je x, pokud x ^ (1/3) = 3 + sqrt (1/4)?

Za prvé, můžete zjednodušit #sqrt (1/4) #:

#sqrt (1/4) = sqrt (1) / sqrt (4) = 1/2 #

Tohle znamená tamto # 3 + sqrt (1/4) = 3 + 1/2 = 7/2 #.

Nyní máte následující rovnici:

# x ^ (1/3) = 7/2 <=> kořen (3) (x) = 7/2 #

Chcete-li tuto rovnici vyřešit, musíte obejít obě strany:

# root (3) (x) = 7/2 #

# <=> (kořen (3) (x)) ^ 3 = (7/2) ^ 3 #

# <=> x = (7/2) ^ 3 = 7 ^ 3/2 ^ 3 = 343/8 #.

Co je to (sqrt (5+) sqrt (3)) / (sqrt (3+) sqrt (3+) sqrt (5)) - (sqrt (5-) sqrt (3)) / (sqrt (3+) sqrt (3-) sqrt (5))?

2/7 Bereme, A = (sqrt5 + sqrt3) / (sqrt3 + sqrt3 + sqrt5) - (sqrt5-sqrt3) / (sqrt3 + sqrt3-sqrt5) = (sqrt5 + sqrt3) / (2sqrt3 + sqrt5) - (sqrt5 + sqrt3) -sqrt3) / (2sqrt3-sqrt5) = (sqrt5 + sqrt3) / (2sqrt3 + sqrt5) - (sqrt5-sqrt3) / (2sqrt3-sqrt5) = ((sqrt5 + sqrt3) (2sqrt3-sqrt5) - (sqrt5-sqrt3) (2sqrt3-sqrt5) - (sqrt5-sqrt3) ) (2sqrt3 + sqrt5)) / ((2sqrt3 + sqrt5) (2sqrt3-sqrt5) = ((2sqrt15-5 + 2 * 3-sqrt15) - (2sqrt15 + 5-2 * 3-sqrt15)) / ((2sqrt15 + 5-2 * 3-sqrt15)) / ((2sqrt3) ^ 2- (sqrt5) ^ 2) = (zrušit (2sqrt15) -5 + 2 * 3cancel (-sqrt15) - zrušit (2sqrt15) -5 + 2 * 3 + zrušit (sqrt15)) / (12-5) = ( -10 + 12) / 7 =

Jak to zjednodušíte (1 / sqrt (a-1) + sqrt (a + 1)) / (1 / sqrt (a + 1) -1 / sqrt (a-1)) div sqrt (a + 1) / ( (a-1) sqrt (a + 1) - (a + 1) sqrt (a-1)), a> 1?

Obrovské matematické formátování ...> barva (modrá) (((1 / sqrt (a-1) + sqrt (a + 1)) / (1 / sqrt (a + 1) -1 / sqrt (a-1)) ) / (sqrt (a + 1) / ((a-1) sqrt (a + 1) - (a + 1) sqrt (a-1)) = barva (červená) (((1 / sqrt (a- 1) + sqrt (a + 1)) / ((sqrt (a-1) -sqrt (a + 1)) / (sqrt (a + 1) cdot sqrt (a-1))) / (sqrt (a) +1) / (sqrt (a-1) cdot sqrt (a-1) cdot sqrt (a + 1) -sqrt (a + 1) cdot sqrt (a + 1) sqrt (a-1)) = barva ( modrá) (((1 / sqrt (a-1) + sqrt (a + 1)) / ((sqrt (a-1) -sqrt (a + 1)) / (sqrt (a + 1) cdot sqrt (a -1))) / (sqrt (a + 1) / (sqrt (a + 1) cdot sqrt (a-1) (sqrt (a-1) -

Pokud x = sqrt3 / 2 pak {sqrt (1 + x) + sqrt (1-x)} / {sqrt (1 + x) - sqrt (1-x)}?

Můžete začít racionalizací: (sqrt (1 + x) + sqrt (1-x)) / (sqrt (1 + x) -sqrt (1-x)) × (sqrt (1 + x) + sqrt (1- x)) / (sqrt (1 + x) + sqrt (1-x)) = = (sqrt (1 + x) + sqrt (1-x)) ^ 2 / (2x) = = ((1 + x) + 2sqrt (1 + x) sqrt (1-x) + (1-x)) / (2x) = = (2 + 2sqrt (1-x ^ 2)) / (2x) = = (1 + sqrt (1 -x ^ 2)) / (x) = Nahrazení: x = sqrt (3) / 2 získáte: = (1 + sqrt (1- 3/4)) / (sqrt (3) / 2) = (1+ 1/2) * (2 / sqrt (3)) = = 3/2 * 2 / sqrt (3) = 3 / sqrt (3) = 3 / sqrt (3) * sqrt (3) / sqrt (3) = sqrt (3) Doufám, že to je to, co jste potřebovali! :-)